Integrand size = 22, antiderivative size = 190 \[ \int \csc ^3(a+b x) \sin ^{\frac {9}{2}}(2 a+2 b x) \, dx=-\frac {7 \arcsin (\cos (a+b x)-\sin (a+b x))}{8 b}+\frac {7 \log \left (\cos (a+b x)+\sin (a+b x)+\sqrt {\sin (2 a+2 b x)}\right )}{8 b}-\frac {7 \cos (a+b x) \sqrt {\sin (2 a+2 b x)}}{4 b}+\frac {7 \sin (a+b x) \sin ^{\frac {3}{2}}(2 a+2 b x)}{6 b}-\frac {14 \cos (a+b x) \sin ^{\frac {5}{2}}(2 a+2 b x)}{15 b}+\frac {4 \sin (a+b x) \sin ^{\frac {7}{2}}(2 a+2 b x)}{5 b}+\frac {\csc ^3(a+b x) \sin ^{\frac {11}{2}}(2 a+2 b x)}{5 b} \]
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Time = 0.25 (sec) , antiderivative size = 190, normalized size of antiderivative = 1.00, number of steps used = 7, number of rules used = 5, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.227, Rules used = {4385, 4393, 4386, 4387, 4390} \[ \int \csc ^3(a+b x) \sin ^{\frac {9}{2}}(2 a+2 b x) \, dx=-\frac {7 \arcsin (\cos (a+b x)-\sin (a+b x))}{8 b}+\frac {4 \sin (a+b x) \sin ^{\frac {7}{2}}(2 a+2 b x)}{5 b}+\frac {7 \sin (a+b x) \sin ^{\frac {3}{2}}(2 a+2 b x)}{6 b}-\frac {14 \sin ^{\frac {5}{2}}(2 a+2 b x) \cos (a+b x)}{15 b}-\frac {7 \sqrt {\sin (2 a+2 b x)} \cos (a+b x)}{4 b}+\frac {\sin ^{\frac {11}{2}}(2 a+2 b x) \csc ^3(a+b x)}{5 b}+\frac {7 \log \left (\sin (a+b x)+\sqrt {\sin (2 a+2 b x)}+\cos (a+b x)\right )}{8 b} \]
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Rule 4385
Rule 4386
Rule 4387
Rule 4390
Rule 4393
Rubi steps \begin{align*} \text {integral}& = \frac {\csc ^3(a+b x) \sin ^{\frac {11}{2}}(2 a+2 b x)}{5 b}+\frac {16}{5} \int \csc (a+b x) \sin ^{\frac {9}{2}}(2 a+2 b x) \, dx \\ & = \frac {\csc ^3(a+b x) \sin ^{\frac {11}{2}}(2 a+2 b x)}{5 b}+\frac {32}{5} \int \cos (a+b x) \sin ^{\frac {7}{2}}(2 a+2 b x) \, dx \\ & = \frac {4 \sin (a+b x) \sin ^{\frac {7}{2}}(2 a+2 b x)}{5 b}+\frac {\csc ^3(a+b x) \sin ^{\frac {11}{2}}(2 a+2 b x)}{5 b}+\frac {28}{5} \int \sin (a+b x) \sin ^{\frac {5}{2}}(2 a+2 b x) \, dx \\ & = -\frac {14 \cos (a+b x) \sin ^{\frac {5}{2}}(2 a+2 b x)}{15 b}+\frac {4 \sin (a+b x) \sin ^{\frac {7}{2}}(2 a+2 b x)}{5 b}+\frac {\csc ^3(a+b x) \sin ^{\frac {11}{2}}(2 a+2 b x)}{5 b}+\frac {14}{3} \int \cos (a+b x) \sin ^{\frac {3}{2}}(2 a+2 b x) \, dx \\ & = \frac {7 \sin (a+b x) \sin ^{\frac {3}{2}}(2 a+2 b x)}{6 b}-\frac {14 \cos (a+b x) \sin ^{\frac {5}{2}}(2 a+2 b x)}{15 b}+\frac {4 \sin (a+b x) \sin ^{\frac {7}{2}}(2 a+2 b x)}{5 b}+\frac {\csc ^3(a+b x) \sin ^{\frac {11}{2}}(2 a+2 b x)}{5 b}+\frac {7}{2} \int \sin (a+b x) \sqrt {\sin (2 a+2 b x)} \, dx \\ & = -\frac {7 \cos (a+b x) \sqrt {\sin (2 a+2 b x)}}{4 b}+\frac {7 \sin (a+b x) \sin ^{\frac {3}{2}}(2 a+2 b x)}{6 b}-\frac {14 \cos (a+b x) \sin ^{\frac {5}{2}}(2 a+2 b x)}{15 b}+\frac {4 \sin (a+b x) \sin ^{\frac {7}{2}}(2 a+2 b x)}{5 b}+\frac {\csc ^3(a+b x) \sin ^{\frac {11}{2}}(2 a+2 b x)}{5 b}+\frac {7}{4} \int \frac {\cos (a+b x)}{\sqrt {\sin (2 a+2 b x)}} \, dx \\ & = -\frac {7 \arcsin (\cos (a+b x)-\sin (a+b x))}{8 b}+\frac {7 \log \left (\cos (a+b x)+\sin (a+b x)+\sqrt {\sin (2 a+2 b x)}\right )}{8 b}-\frac {7 \cos (a+b x) \sqrt {\sin (2 a+2 b x)}}{4 b}+\frac {7 \sin (a+b x) \sin ^{\frac {3}{2}}(2 a+2 b x)}{6 b}-\frac {14 \cos (a+b x) \sin ^{\frac {5}{2}}(2 a+2 b x)}{15 b}+\frac {4 \sin (a+b x) \sin ^{\frac {7}{2}}(2 a+2 b x)}{5 b}+\frac {\csc ^3(a+b x) \sin ^{\frac {11}{2}}(2 a+2 b x)}{5 b} \\ \end{align*}
Time = 0.96 (sec) , antiderivative size = 100, normalized size of antiderivative = 0.53 \[ \int \csc ^3(a+b x) \sin ^{\frac {9}{2}}(2 a+2 b x) \, dx=\frac {7 \left (-\arcsin (\cos (a+b x)-\sin (a+b x))+\log \left (\cos (a+b x)+\sin (a+b x)+\sqrt {\sin (2 (a+b x))}\right )\right )-\frac {2}{3} (10 \cos (a+b x)+9 \cos (3 (a+b x))+2 \cos (5 (a+b x))) \sqrt {\sin (2 (a+b x))}}{8 b} \]
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Result contains higher order function than in optimal. Order 4 vs. order 3.
Time = 105.30 (sec) , antiderivative size = 441, normalized size of antiderivative = 2.32
method | result | size |
default | \(-\frac {64 \sqrt {-\frac {\tan \left (\frac {a}{2}+\frac {x b}{2}\right )}{\tan \left (\frac {a}{2}+\frac {x b}{2}\right )^{2}-1}}\, \left (\sqrt {\tan \left (\frac {a}{2}+\frac {x b}{2}\right )+1}\, \sqrt {-2 \tan \left (\frac {a}{2}+\frac {x b}{2}\right )+2}\, \sqrt {-\tan \left (\frac {a}{2}+\frac {x b}{2}\right )}\, \operatorname {EllipticF}\left (\sqrt {\tan \left (\frac {a}{2}+\frac {x b}{2}\right )+1}, \frac {\sqrt {2}}{2}\right ) \tan \left (\frac {a}{2}+\frac {x b}{2}\right )^{6}-3 \sqrt {\tan \left (\frac {a}{2}+\frac {x b}{2}\right )+1}\, \sqrt {-2 \tan \left (\frac {a}{2}+\frac {x b}{2}\right )+2}\, \sqrt {-\tan \left (\frac {a}{2}+\frac {x b}{2}\right )}\, \operatorname {EllipticF}\left (\sqrt {\tan \left (\frac {a}{2}+\frac {x b}{2}\right )+1}, \frac {\sqrt {2}}{2}\right ) \tan \left (\frac {a}{2}+\frac {x b}{2}\right )^{4}+2 \tan \left (\frac {a}{2}+\frac {x b}{2}\right )^{7}+3 \sqrt {\tan \left (\frac {a}{2}+\frac {x b}{2}\right )+1}\, \sqrt {-2 \tan \left (\frac {a}{2}+\frac {x b}{2}\right )+2}\, \sqrt {-\tan \left (\frac {a}{2}+\frac {x b}{2}\right )}\, \operatorname {EllipticF}\left (\sqrt {\tan \left (\frac {a}{2}+\frac {x b}{2}\right )+1}, \frac {\sqrt {2}}{2}\right ) \tan \left (\frac {a}{2}+\frac {x b}{2}\right )^{2}+10 \tan \left (\frac {a}{2}+\frac {x b}{2}\right )^{5}-\sqrt {\tan \left (\frac {a}{2}+\frac {x b}{2}\right )+1}\, \sqrt {-2 \tan \left (\frac {a}{2}+\frac {x b}{2}\right )+2}\, \sqrt {-\tan \left (\frac {a}{2}+\frac {x b}{2}\right )}\, \operatorname {EllipticF}\left (\sqrt {\tan \left (\frac {a}{2}+\frac {x b}{2}\right )+1}, \frac {\sqrt {2}}{2}\right )+10 \tan \left (\frac {a}{2}+\frac {x b}{2}\right )^{3}+2 \tan \left (\frac {a}{2}+\frac {x b}{2}\right )\right )}{21 \sqrt {\tan \left (\frac {a}{2}+\frac {x b}{2}\right ) \left (\tan \left (\frac {a}{2}+\frac {x b}{2}\right )^{2}-1\right )}\, \left (\tan \left (\frac {a}{2}+\frac {x b}{2}\right )-1\right )^{2} \sqrt {\tan \left (\frac {a}{2}+\frac {x b}{2}\right )^{3}-\tan \left (\frac {a}{2}+\frac {x b}{2}\right )}\, \left (\tan \left (\frac {a}{2}+\frac {x b}{2}\right )+1\right )^{2} b}\) | \(441\) |
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Time = 0.27 (sec) , antiderivative size = 291, normalized size of antiderivative = 1.53 \[ \int \csc ^3(a+b x) \sin ^{\frac {9}{2}}(2 a+2 b x) \, dx=-\frac {8 \, \sqrt {2} {\left (32 \, \cos \left (b x + a\right )^{5} - 4 \, \cos \left (b x + a\right )^{3} - 7 \, \cos \left (b x + a\right )\right )} \sqrt {\cos \left (b x + a\right ) \sin \left (b x + a\right )} - 42 \, \arctan \left (-\frac {\sqrt {2} \sqrt {\cos \left (b x + a\right ) \sin \left (b x + a\right )} {\left (\cos \left (b x + a\right ) - \sin \left (b x + a\right )\right )} + \cos \left (b x + a\right ) \sin \left (b x + a\right )}{\cos \left (b x + a\right )^{2} + 2 \, \cos \left (b x + a\right ) \sin \left (b x + a\right ) - 1}\right ) + 42 \, \arctan \left (-\frac {2 \, \sqrt {2} \sqrt {\cos \left (b x + a\right ) \sin \left (b x + a\right )} - \cos \left (b x + a\right ) - \sin \left (b x + a\right )}{\cos \left (b x + a\right ) - \sin \left (b x + a\right )}\right ) + 21 \, \log \left (-32 \, \cos \left (b x + a\right )^{4} + 4 \, \sqrt {2} {\left (4 \, \cos \left (b x + a\right )^{3} - {\left (4 \, \cos \left (b x + a\right )^{2} + 1\right )} \sin \left (b x + a\right ) - 5 \, \cos \left (b x + a\right )\right )} \sqrt {\cos \left (b x + a\right ) \sin \left (b x + a\right )} + 32 \, \cos \left (b x + a\right )^{2} + 16 \, \cos \left (b x + a\right ) \sin \left (b x + a\right ) + 1\right )}{96 \, b} \]
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Timed out. \[ \int \csc ^3(a+b x) \sin ^{\frac {9}{2}}(2 a+2 b x) \, dx=\text {Timed out} \]
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\[ \int \csc ^3(a+b x) \sin ^{\frac {9}{2}}(2 a+2 b x) \, dx=\int { \csc \left (b x + a\right )^{3} \sin \left (2 \, b x + 2 \, a\right )^{\frac {9}{2}} \,d x } \]
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\[ \int \csc ^3(a+b x) \sin ^{\frac {9}{2}}(2 a+2 b x) \, dx=\int { \csc \left (b x + a\right )^{3} \sin \left (2 \, b x + 2 \, a\right )^{\frac {9}{2}} \,d x } \]
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Timed out. \[ \int \csc ^3(a+b x) \sin ^{\frac {9}{2}}(2 a+2 b x) \, dx=\int \frac {{\sin \left (2\,a+2\,b\,x\right )}^{9/2}}{{\sin \left (a+b\,x\right )}^3} \,d x \]
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